Optimal. Leaf size=278 \[ -\frac {a \left (20 a^2-69 b^2\right ) \sin ^4(c+d x) \cos (c+d x)}{840 b d}-\frac {\left (20 a^2-63 b^2\right ) \sin ^3(c+d x) \cos (c+d x) (a+b \sin (c+d x))^2}{336 b^2 d}-\frac {\left (8 a^2+3 b^2\right ) \sin (c+d x) \cos (c+d x)}{128 d}+\frac {1}{128} x \left (8 a^2+3 b^2\right )-\frac {\left (40 a^4-140 a^2 b^2+21 b^4\right ) \sin ^3(c+d x) \cos (c+d x)}{1344 b^2 d}+\frac {5 a \sin ^3(c+d x) \cos (c+d x) (a+b \sin (c+d x))^3}{56 b^2 d}+\frac {2 a b \cos ^3(c+d x)}{35 d}-\frac {6 a b \cos (c+d x)}{35 d}-\frac {\sin ^4(c+d x) \cos (c+d x) (a+b \sin (c+d x))^3}{8 b d} \]
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Rubi [A] time = 0.63, antiderivative size = 278, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.276, Rules used = {2895, 3049, 3033, 3023, 2748, 2635, 8, 2633} \[ -\frac {a \left (20 a^2-69 b^2\right ) \sin ^4(c+d x) \cos (c+d x)}{840 b d}-\frac {\left (20 a^2-63 b^2\right ) \sin ^3(c+d x) \cos (c+d x) (a+b \sin (c+d x))^2}{336 b^2 d}-\frac {\left (-140 a^2 b^2+40 a^4+21 b^4\right ) \sin ^3(c+d x) \cos (c+d x)}{1344 b^2 d}-\frac {\left (8 a^2+3 b^2\right ) \sin (c+d x) \cos (c+d x)}{128 d}+\frac {1}{128} x \left (8 a^2+3 b^2\right )+\frac {5 a \sin ^3(c+d x) \cos (c+d x) (a+b \sin (c+d x))^3}{56 b^2 d}+\frac {2 a b \cos ^3(c+d x)}{35 d}-\frac {6 a b \cos (c+d x)}{35 d}-\frac {\sin ^4(c+d x) \cos (c+d x) (a+b \sin (c+d x))^3}{8 b d} \]
Antiderivative was successfully verified.
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Rule 8
Rule 2633
Rule 2635
Rule 2748
Rule 2895
Rule 3023
Rule 3033
Rule 3049
Rubi steps
\begin {align*} \int \cos ^4(c+d x) \sin ^2(c+d x) (a+b \sin (c+d x))^2 \, dx &=\frac {5 a \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^3}{56 b^2 d}-\frac {\cos (c+d x) \sin ^4(c+d x) (a+b \sin (c+d x))^3}{8 b d}-\frac {\int \sin ^2(c+d x) (a+b \sin (c+d x))^2 \left (15 a^2-56 b^2+2 a b \sin (c+d x)-\left (20 a^2-63 b^2\right ) \sin ^2(c+d x)\right ) \, dx}{56 b^2}\\ &=-\frac {\left (20 a^2-63 b^2\right ) \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^2}{336 b^2 d}+\frac {5 a \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^3}{56 b^2 d}-\frac {\cos (c+d x) \sin ^4(c+d x) (a+b \sin (c+d x))^3}{8 b d}-\frac {\int \sin ^2(c+d x) (a+b \sin (c+d x)) \left (3 a \left (10 a^2-49 b^2\right )+b \left (2 a^2-21 b^2\right ) \sin (c+d x)-2 a \left (20 a^2-69 b^2\right ) \sin ^2(c+d x)\right ) \, dx}{336 b^2}\\ &=-\frac {a \left (20 a^2-69 b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{840 b d}-\frac {\left (20 a^2-63 b^2\right ) \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^2}{336 b^2 d}+\frac {5 a \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^3}{56 b^2 d}-\frac {\cos (c+d x) \sin ^4(c+d x) (a+b \sin (c+d x))^3}{8 b d}-\frac {\int \sin ^2(c+d x) \left (15 a^2 \left (10 a^2-49 b^2\right )-288 a b^3 \sin (c+d x)-5 \left (40 a^4-140 a^2 b^2+21 b^4\right ) \sin ^2(c+d x)\right ) \, dx}{1680 b^2}\\ &=-\frac {\left (40 a^4-140 a^2 b^2+21 b^4\right ) \cos (c+d x) \sin ^3(c+d x)}{1344 b^2 d}-\frac {a \left (20 a^2-69 b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{840 b d}-\frac {\left (20 a^2-63 b^2\right ) \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^2}{336 b^2 d}+\frac {5 a \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^3}{56 b^2 d}-\frac {\cos (c+d x) \sin ^4(c+d x) (a+b \sin (c+d x))^3}{8 b d}-\frac {\int \sin ^2(c+d x) \left (-105 b^2 \left (8 a^2+3 b^2\right )-1152 a b^3 \sin (c+d x)\right ) \, dx}{6720 b^2}\\ &=-\frac {\left (40 a^4-140 a^2 b^2+21 b^4\right ) \cos (c+d x) \sin ^3(c+d x)}{1344 b^2 d}-\frac {a \left (20 a^2-69 b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{840 b d}-\frac {\left (20 a^2-63 b^2\right ) \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^2}{336 b^2 d}+\frac {5 a \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^3}{56 b^2 d}-\frac {\cos (c+d x) \sin ^4(c+d x) (a+b \sin (c+d x))^3}{8 b d}+\frac {1}{35} (6 a b) \int \sin ^3(c+d x) \, dx-\frac {1}{64} \left (-8 a^2-3 b^2\right ) \int \sin ^2(c+d x) \, dx\\ &=-\frac {\left (8 a^2+3 b^2\right ) \cos (c+d x) \sin (c+d x)}{128 d}-\frac {\left (40 a^4-140 a^2 b^2+21 b^4\right ) \cos (c+d x) \sin ^3(c+d x)}{1344 b^2 d}-\frac {a \left (20 a^2-69 b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{840 b d}-\frac {\left (20 a^2-63 b^2\right ) \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^2}{336 b^2 d}+\frac {5 a \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^3}{56 b^2 d}-\frac {\cos (c+d x) \sin ^4(c+d x) (a+b \sin (c+d x))^3}{8 b d}-\frac {1}{128} \left (-8 a^2-3 b^2\right ) \int 1 \, dx-\frac {(6 a b) \operatorname {Subst}\left (\int \left (1-x^2\right ) \, dx,x,\cos (c+d x)\right )}{35 d}\\ &=\frac {1}{128} \left (8 a^2+3 b^2\right ) x-\frac {6 a b \cos (c+d x)}{35 d}+\frac {2 a b \cos ^3(c+d x)}{35 d}-\frac {\left (8 a^2+3 b^2\right ) \cos (c+d x) \sin (c+d x)}{128 d}-\frac {\left (40 a^4-140 a^2 b^2+21 b^4\right ) \cos (c+d x) \sin ^3(c+d x)}{1344 b^2 d}-\frac {a \left (20 a^2-69 b^2\right ) \cos (c+d x) \sin ^4(c+d x)}{840 b d}-\frac {\left (20 a^2-63 b^2\right ) \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^2}{336 b^2 d}+\frac {5 a \cos (c+d x) \sin ^3(c+d x) (a+b \sin (c+d x))^3}{56 b^2 d}-\frac {\cos (c+d x) \sin ^4(c+d x) (a+b \sin (c+d x))^3}{8 b d}\\ \end {align*}
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Mathematica [A] time = 0.62, size = 141, normalized size = 0.51 \[ \frac {840 a^2 \sin (2 (c+d x))-840 a^2 \sin (4 (c+d x))-280 a^2 \sin (6 (c+d x))+3360 a^2 d x-5040 a b \cos (c+d x)-1680 a b \cos (3 (c+d x))+336 a b \cos (5 (c+d x))+240 a b \cos (7 (c+d x))-420 b^2 \sin (4 (c+d x))+\frac {105}{2} b^2 \sin (8 (c+d x))+1680 b^2 c+1260 b^2 d x}{53760 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.75, size = 128, normalized size = 0.46 \[ \frac {3840 \, a b \cos \left (d x + c\right )^{7} - 5376 \, a b \cos \left (d x + c\right )^{5} + 105 \, {\left (8 \, a^{2} + 3 \, b^{2}\right )} d x + 35 \, {\left (48 \, b^{2} \cos \left (d x + c\right )^{7} - 8 \, {\left (8 \, a^{2} + 9 \, b^{2}\right )} \cos \left (d x + c\right )^{5} + 2 \, {\left (8 \, a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )^{3} + 3 \, {\left (8 \, a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{13440 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.31, size = 150, normalized size = 0.54 \[ \frac {1}{128} \, {\left (8 \, a^{2} + 3 \, b^{2}\right )} x + \frac {a b \cos \left (7 \, d x + 7 \, c\right )}{224 \, d} + \frac {a b \cos \left (5 \, d x + 5 \, c\right )}{160 \, d} - \frac {a b \cos \left (3 \, d x + 3 \, c\right )}{32 \, d} - \frac {3 \, a b \cos \left (d x + c\right )}{32 \, d} + \frac {b^{2} \sin \left (8 \, d x + 8 \, c\right )}{1024 \, d} - \frac {a^{2} \sin \left (6 \, d x + 6 \, c\right )}{192 \, d} + \frac {a^{2} \sin \left (2 \, d x + 2 \, c\right )}{64 \, d} - \frac {{\left (2 \, a^{2} + b^{2}\right )} \sin \left (4 \, d x + 4 \, c\right )}{128 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.33, size = 163, normalized size = 0.59 \[ \frac {a^{2} \left (-\frac {\sin \left (d x +c \right ) \left (\cos ^{5}\left (d x +c \right )\right )}{6}+\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{24}+\frac {d x}{16}+\frac {c}{16}\right )+2 a b \left (-\frac {\left (\sin ^{2}\left (d x +c \right )\right ) \left (\cos ^{5}\left (d x +c \right )\right )}{7}-\frac {2 \left (\cos ^{5}\left (d x +c \right )\right )}{35}\right )+b^{2} \left (-\frac {\left (\sin ^{3}\left (d x +c \right )\right ) \left (\cos ^{5}\left (d x +c \right )\right )}{8}-\frac {\sin \left (d x +c \right ) \left (\cos ^{5}\left (d x +c \right )\right )}{16}+\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{64}+\frac {3 d x}{128}+\frac {3 c}{128}\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.35, size = 101, normalized size = 0.36 \[ \frac {560 \, {\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} + 12 \, d x + 12 \, c - 3 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2} + 6144 \, {\left (5 \, \cos \left (d x + c\right )^{7} - 7 \, \cos \left (d x + c\right )^{5}\right )} a b + 105 \, {\left (24 \, d x + 24 \, c + \sin \left (8 \, d x + 8 \, c\right ) - 8 \, \sin \left (4 \, d x + 4 \, c\right )\right )} b^{2}}{107520 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 9.94, size = 139, normalized size = 0.50 \[ \frac {210\,a^2\,\sin \left (2\,c+2\,d\,x\right )-210\,a^2\,\sin \left (4\,c+4\,d\,x\right )-70\,a^2\,\sin \left (6\,c+6\,d\,x\right )-105\,b^2\,\sin \left (4\,c+4\,d\,x\right )+\frac {105\,b^2\,\sin \left (8\,c+8\,d\,x\right )}{8}-1260\,a\,b\,\cos \left (c+d\,x\right )-420\,a\,b\,\cos \left (3\,c+3\,d\,x\right )+84\,a\,b\,\cos \left (5\,c+5\,d\,x\right )+60\,a\,b\,\cos \left (7\,c+7\,d\,x\right )+840\,a^2\,d\,x+315\,b^2\,d\,x}{13440\,d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 9.87, size = 420, normalized size = 1.51 \[ \begin {cases} \frac {a^{2} x \sin ^{6}{\left (c + d x \right )}}{16} + \frac {3 a^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{16} + \frac {3 a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{16} + \frac {a^{2} x \cos ^{6}{\left (c + d x \right )}}{16} + \frac {a^{2} \sin ^{5}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{16 d} + \frac {a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{6 d} - \frac {a^{2} \sin {\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{16 d} - \frac {2 a b \sin ^{2}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{5 d} - \frac {4 a b \cos ^{7}{\left (c + d x \right )}}{35 d} + \frac {3 b^{2} x \sin ^{8}{\left (c + d x \right )}}{128} + \frac {3 b^{2} x \sin ^{6}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{32} + \frac {9 b^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{64} + \frac {3 b^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{32} + \frac {3 b^{2} x \cos ^{8}{\left (c + d x \right )}}{128} + \frac {3 b^{2} \sin ^{7}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{128 d} + \frac {11 b^{2} \sin ^{5}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{128 d} - \frac {11 b^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{128 d} - \frac {3 b^{2} \sin {\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{128 d} & \text {for}\: d \neq 0 \\x \left (a + b \sin {\relax (c )}\right )^{2} \sin ^{2}{\relax (c )} \cos ^{4}{\relax (c )} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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